5y^4-5y^2+2=0

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Solution for 5y^4-5y^2+2=0 equation:


Simplifying
5y4 + -5y2 + 2 = 0

Reorder the terms:
2 + -5y2 + 5y4 = 0

Solving
2 + -5y2 + 5y4 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.4 + -1y2 + y4 = 0

Move the constant term to the right:

Add '-0.4' to each side of the equation.
0.4 + -1y2 + -0.4 + y4 = 0 + -0.4

Reorder the terms:
0.4 + -0.4 + -1y2 + y4 = 0 + -0.4

Combine like terms: 0.4 + -0.4 = 0.0
0.0 + -1y2 + y4 = 0 + -0.4
-1y2 + y4 = 0 + -0.4

Combine like terms: 0 + -0.4 = -0.4
-1y2 + y4 = -0.4

The y term is -1y2.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1y2 + 0.25 + y4 = -0.4 + 0.25

Reorder the terms:
0.25 + -1y2 + y4 = -0.4 + 0.25

Combine like terms: -0.4 + 0.25 = -0.15
0.25 + -1y2 + y4 = -0.15

Factor a perfect square on the left side:
(y2 + -0.5)(y2 + -0.5) = -0.15

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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